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It is incredibly difficult...
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By (user no longer on site) OP
over a year ago
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To calculate the velocity required to escape the gravitational influence of a planet.
Also quite tricky to fight off boredom while freezing my arse off in Salisbury.
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By (user no longer on site)
over a year ago
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"To calculate the velocity required to escape the gravitational influence of a planet.
Also quite tricky to fight off boredom while freezing my arse off in Salisbury.
"
I would work on the second conundrum ..... |
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Complicated, certainly, but you just need to know the variables...
You can determine the correct units by going through the equation with units. It’s important to always state units at the end of each problem and ensure that they are correct. The units of velocity are always m/s, so when you are done with the equation you should end up with m/s.
* The unit of G is N-m2/kg2, R is m, and M is kg.
* It’s also helpful to know that 1 Newton is equal to 1 kg-m/s2.[7]
* For our equation v(2GM/R) = v((N-m2/kg2x kg)/m)
* Canceling out one meter and one kilogram unit gives you v(N-m)/kg
* Replacing N with kg-m/s2 gives you v(kg-m/s2)(m/kg)
* Canceling out the kg gives you vm2/s2
* Taking the square root gives you m/s, the unit for velocity.
* You can convert this to km/s by multiplying by the conversion factor (1 km/1000 m).
http://www.wikihow.com/Calculate-Escape-Velocity |
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By (user no longer on site)
over a year ago
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"Complicated, certainly, but you just need to know the variables...
You can determine the correct units by going through the equation with units. It’s important to always state units at the end of each problem and ensure that they are correct. The units of velocity are always m/s, so when you are done with the equation you should end up with m/s.
* The unit of G is N-m2/kg2, R is m, and M is kg.
* It’s also helpful to know that 1 Newton is equal to 1 kg-m/s2.[7]
* For our equation v(2GM/R) = v((N-m2/kg2x kg)/m)
* Canceling out one meter and one kilogram unit gives you v(N-m)/kg
* Replacing N with kg-m/s2 gives you v(kg-m/s2)(m/kg)
* Canceling out the kg gives you vm2/s2
* Taking the square root gives you m/s, the unit for velocity.
* You can convert this to km/s by multiplying by the conversion factor (1 km/1000 m).
http://www.wikihow.com/Calculate-Escape-Velocity"
Much prefer the magnet theory  |
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"Complicated, certainly, but you just need to know the variables...
You can determine the correct units by going through the equation with units. It’s important to always state units at the end of each problem and ensure that they are correct. The units of velocity are always m/s, so when you are done with the equation you should end up with m/s.
* The unit of G is N-m2/kg2, R is m, and M is kg.
* It’s also helpful to know that 1 Newton is equal to 1 kg-m/s2.[7]
* For our equation v(2GM/R) = v((N-m2/kg2x kg)/m)
* Canceling out one meter and one kilogram unit gives you v(N-m)/kg
* Replacing N with kg-m/s2 gives you v(kg-m/s2)(m/kg)
* Canceling out the kg gives you vm2/s2
* Taking the square root gives you m/s, the unit for velocity.
* You can convert this to km/s by multiplying by the conversion factor (1 km/1000 m).
http://www.wikihow.com/Calculate-Escape-Velocity
Much prefer the magnet theory "
Google is your friend!
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By (user no longer on site)
over a year ago
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"Complicated, certainly, but you just need to know the variables...
You can determine the correct units by going through the equation with units. It’s important to always state units at the end of each problem and ensure that they are correct. The units of velocity are always m/s, so when you are done with the equation you should end up with m/s.
* The unit of G is N-m2/kg2, R is m, and M is kg.
* It’s also helpful to know that 1 Newton is equal to 1 kg-m/s2.[7]
* For our equation v(2GM/R) = v((N-m2/kg2x kg)/m)
* Canceling out one meter and one kilogram unit gives you v(N-m)/kg
* Replacing N with kg-m/s2 gives you v(kg-m/s2)(m/kg)
* Canceling out the kg gives you vm2/s2
* Taking the square root gives you m/s, the unit for velocity.
* You can convert this to km/s by multiplying by the conversion factor (1 km/1000 m).
http://www.wikihow.com/Calculate-Escape-Velocity
Much prefer the magnet theory
Google is your friend!
"
I was totally lost after the unit is g .....  |
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By (user no longer on site) OP
over a year ago
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I apreciate the effort haha. Was not expecting that. Magnets would be great if we had a giant vacuum tube, but i think the problems involved in building a 209 mile high structure make it.... complicated .
So, escape velocity to achieve a parabolic orbit is Square root of (2 x gravitational constant x mass of the earth over radius of orbit from the center of the planet)is that what you are saying? Now I just need the Delta V required to achieve such a task. I don't have the mass of the object or the specific impulse because i'm totally making this up. |
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By (user no longer on site)
over a year ago
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"To calculate the velocity required to escape the gravitational influence of a planet.
Also quite tricky to fight off boredom while freezing my arse off in Salisbury.
"
There's a formula - so not too hard |
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"To calculate the velocity required to escape the gravitational influence of a planet.
Also quite tricky to fight off boredom while freezing my arse off in Salisbury.
There's a formula - so not too hard"
Nothing gets past you |
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By (user no longer on site)
over a year ago
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"Complicated, certainly, but you just need to know the variables...
You can determine the correct units by going through the equation with units. It’s important to always state units at the end of each problem and ensure that they are correct. The units of velocity are always m/s, so when you are done with the equation you should end up with m/s.
* The unit of G is N-m2/kg2, R is m, and M is kg.
* It’s also helpful to know that 1 Newton is equal to 1 kg-m/s2.[7]
* For our equation v(2GM/R) = v((N-m2/kg2x kg)/m)
* Canceling out one meter and one kilogram unit gives you v(N-m)/kg
* Replacing N with kg-m/s2 gives you v(kg-m/s2)(m/kg)
* Canceling out the kg gives you vm2/s2
* Taking the square root gives you m/s, the unit for velocity.
* You can convert this to km/s by multiplying by the conversion factor (1 km/1000 m).
http://www.wikihow.com/Calculate-Escape-Velocity
Much prefer the magnet theory
Google is your friend!
"
.
Googles replaced the principia  |
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"To calculate the velocity required to escape the gravitational influence of a planet.
Also quite tricky to fight off boredom while freezing my arse off in Salisbury.
There's a formula - so not too hard
Nothing gets past you"
Having studied this formula I think there may be a slight flaw in the accumulative velocity relative to the period of time and position of the moon at the end X act time for n which one wishes to escape.to account for this you should add.
S =TEP/h. 15/ ta/LK 1 n. 5hxit simples |
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When I woz at skill popular science books did ask how fast must a rocket go to escape the earth. This woz very confusing as a rocket do 10 miles an hour will eventually escape the earth. What they actually meant was how fast must you dude a bullet (ie something with no propellant) for it to escape the earth. I spent a year if my life from 9 to 10 worrying about this but pop science books were bollocks in those days. |
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By (user no longer on site)
over a year ago
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"When I woz at skill popular science books did ask how fast must a rocket go to escape the earth. This woz very confusing as a rocket do 10 miles an hour will eventually escape the earth. What they actually meant was how fast must you dude a bullet (ie something with no propellant) for it to escape the earth. I spent a year if my life from 9 to 10 worrying about this but pop science books were bollocks in those days."
.
You can't escape gravity doing 10mph..
Even if you wait a long time.
It's about 25,000 mph or its back to earth.
If you landed on Jupiter and wished to take off from there it's more like 170,000 mph.
The more mass the more pull.
It's why even light can't escape the gravity of black holes |
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"Complicated, certainly, but you just need to know the variables...
You can determine the correct units by going through the equation with units. It’s important to always state units at the end of each problem and ensure that they are correct. The units of velocity are always m/s, so when you are done with the equation you should end up with m/s.
* The unit of G is N-m2/kg2, R is m, and M is kg.
* It’s also helpful to know that 1 Newton is equal to 1 kg-m/s2.[7]
* For our equation v(2GM/R) = v((N-m2/kg2x kg)/m)
* Canceling out one meter and one kilogram unit gives you v(N-m)/kg
* Replacing N with kg-m/s2 gives you v(kg-m/s2)(m/kg)
* Canceling out the kg gives you vm2/s2
* Taking the square root gives you m/s, the unit for velocity.
* You can convert this to km/s by multiplying by the conversion factor (1 km/1000 m).
http://www.wikihow.com/Calculate-Escape-Velocity
Much prefer the magnet theory
Google is your friend!
.
Googles replaced the principia "
The average A-level Physics student (should) understand the solar system and universe better than Newton |
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By (user no longer on site)
over a year ago
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"When I woz at skill popular science books did ask how fast must a rocket go to escape the earth. This woz very confusing as a rocket do 10 miles an hour will eventually escape the earth. What they actually meant was how fast must you dude a bullet (ie something with no propellant) for it to escape the earth. I spent a year if my life from 9 to 10 worrying about this but pop science books were bollocks in those days..
You can't escape gravity doing 10mph..
Even if you wait a long time.
It's about 25,000 mph or its back to earth.
If you landed on Jupiter and wished to take off from there it's more like 170,000 mph.
The more mass the more pull.
It's why even light can't escape the gravity of black holes"
Actually you could escape gravity doing 1mph.
The fact you are traveling at a constant 1mph vertically shows you are over comming gravity just very very slowly.
You'd need massive amounts of fuel to maintain your crawl into space, which is why we fire things out balistically, massive burst of thrust to get us there without needing more fuel than we can lift.
Both you and him are confusing constant and balistic situations.
Also the confustion between units and speed and acceleration you've both got going on here.
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The only reason a plane can't escape is cos the air gets too thin to generate lift. A Rocket will eventually escape regardless of speed provided it has enough fuel. Escape velocity only applies to unpowered things like rifle bullets. |
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By (user no longer on site)
over a year ago
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"Complicated, certainly, but you just need to know the variables...
You can determine the correct units by going through the equation with units. It’s important to always state units at the end of each problem and ensure that they are correct. The units of velocity are always m/s, so when you are done with the equation you should end up with m/s.
* The unit of G is N-m2/kg2, R is m, and M is kg.
* It’s also helpful to know that 1 Newton is equal to 1 kg-m/s2.[7]
* For our equation v(2GM/R) = v((N-m2/kg2x kg)/m)
* Canceling out one meter and one kilogram unit gives you v(N-m)/kg
* Replacing N with kg-m/s2 gives you v(kg-m/s2)(m/kg)
* Canceling out the kg gives you vm2/s2
* Taking the square root gives you m/s, the unit for velocity.
* You can convert this to km/s by multiplying by the conversion factor (1 km/1000 m).
http://www.wikihow.com/Calculate-Escape-Velocity
Much prefer the magnet theory
Google is your friend!
.
Googles replaced the principia
The average A-level Physics student (should) understand the solar system and universe better than Newton "
.
Yeah, that's how science works!.
Still must be good having wrote a 300 year old science book that's still relevant and used today!.
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By (user no longer on site)
over a year ago
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"The only reason a plane can't escape is cos the air gets too thin to generate lift. A Rocket will eventually escape regardless of speed provided it has enough fuel. Escape velocity only applies to unpowered things like rifle bullets."
See skylon/reaction engines for a fantastix solution to the high altitude jet problem.
Project orian was also a fascinating concept that would provide a possibility for colonising other bodies. |
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"The only reason a plane can't escape is cos the air gets too thin to generate lift. A Rocket will eventually escape regardless of speed provided it has enough fuel. Escape velocity only applies to unpowered things like rifle bullets.
See skylon/reaction engines for a fantastix solution to the high altitude jet problem.
Project orian was also a fascinating concept that would provide a possibility for colonising other bodies."
Project Orion is ridiculous! LOL |
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"The only reason a plane can't escape is cos the air gets too thin to generate lift. A Rocket will eventually escape regardless of speed provided it has enough fuel. Escape velocity only applies to unpowered things like rifle bullets.
See skylon/reaction engines for a fantastix solution to the high altitude jet problem.
Project orian was also a fascinating concept that would provide a possibility for colonising other bodies.
Project Orion is ridiculous! LOL"
What could possibly go wrong?! |
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By (user no longer on site)
over a year ago
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"The only reason a plane can't escape is cos the air gets too thin to generate lift. A Rocket will eventually escape regardless of speed provided it has enough fuel. Escape velocity only applies to unpowered things like rifle bullets.
See skylon/reaction engines for a fantastix solution to the high altitude jet problem.
Project orian was also a fascinating concept that would provide a possibility for colonising other bodies.
Project Orion is ridiculous! LOL"
Viable though.
Not the cleanest way up but theoretically it is sound in principal.
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By (user no longer on site)
over a year ago
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"There was a Skylon at the 1951 Festival of Britain"
Well there was hatol(sp?) in the 80's same engineer but fundamentally flawed originally.
What skylon are you talking about?
Edit: googling revelas cool sculpture.
I was gutted i missed a lecture from the guy behind reaction engines at work cause i was on holdiday last year  |
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By (user no longer on site)
over a year ago
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"Complicated, certainly, but you just need to know the variables...
You can determine the correct units by going through the equation with units. It’s important to always state units at the end of each problem and ensure that they are correct. The units of velocity are always m/s, so when you are done with the equation you should end up with m/s.
* The unit of G is N-m2/kg2, R is m, and M is kg.
* It’s also helpful to know that 1 Newton is equal to 1 kg-m/s2.[7]
* For our equation v(2GM/R) = v((N-m2/kg2x kg)/m)
* Canceling out one meter and one kilogram unit gives you v(N-m)/kg
* Replacing N with kg-m/s2 gives you v(kg-m/s2)(m/kg)
* Canceling out the kg gives you vm2/s2
* Taking the square root gives you m/s, the unit for velocity.
* You can convert this to km/s by multiplying by the conversion factor (1 km/1000 m).
http://www.wikihow.com/Calculate-Escape-Velocity"
I'm in LOVE ....
Mwah |
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By *aucy3Couple
over a year ago
glasgow |
"To calculate the velocity required to escape the gravitational influence of a planet.
Also quite tricky to fight off boredom while freezing my arse off in Salisbury.
"
It's,2.34 times the velocity,
minus 1.5 times the gravitational pull,+a wee bit of black matter.
Ffs!!! I thought everybody knew that.
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By (user no longer on site)
over a year ago
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"Slightly off topic still science based - have forumites heard about immune bubbles?
Future tech X
Mwah "
What are they googling immune bubbles only brings up references to Eve online :p |
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"Slightly off topic still science based - have forumites heard about immune bubbles?
Future tech X
Mwah
What are they googling immune bubbles only brings up references to Eve online :p"
And what is cowardly guys about? Kelly Brook in a rubber dress? Just to keep it consistent. |
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By (user no longer on site)
over a year ago
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Immune bubbles .....delivery using ur own immune system ....
The cancer drug paclitaxel just got more effective. For the first time, researchers from the University of North Carolina at Chapel Hill have packaged it in containers derived from a patient’s own immune system, protecting the drug from being destroyed by the body’s own defenses and bringing the entire payload to the tumor.
“That means we can use 50 times less of the drug and still get the same results,” said Elena Batrakova, Ph.D., an associate professor in the UNC Eshelman School of Pharmacy.
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