FabSwingers.com
 

FabSwingers.com > Forums > The Lounge > Any engineers in the forum?

Any engineers in the forum?

Jump to: Newest in thread

 

By (user no longer on site) OP     over a year ago

This is desperation but are there any engineers or mathematitians who understand Virtual Work on an Inderterminmate Beam that fancy helping me solve a question?

I feel cheecky for posting this but hey what the hell lol

Reply privately, Reply in forum +quote or View forums list

 

By (user no longer on site)  over a year ago

yeah,all you have to do is Using equation (1), solve for YB:

-63200 (k-ft3)/EI + 2666.67 (k-ft3)/EI * YB = 0

YB = 23.7

Multiply the unit load, Q, at YB by 23.7 to get the final reaction. The positive answer indicates that the reaction is in the direction of the applied unit force.

simples

Reply privately, Reply in forum +quote or View forums list

 

By *ittle_brat_evie!!Woman  over a year ago

evesham

yeah but to truely learn you must do it yourself so for your own good i am not going to help you

Reply privately, Reply in forum +quote or View forums list

 

By (user no longer on site) OP     over a year ago


"yeah,all you have to do is Using equation (1), solve for YB:

-63200 (k-ft3)/EI + 2666.67 (k-ft3)/EI * YB = 0

YB = 23.7

Multiply the unit load, Q, at YB by 23.7 to get the final reaction. The positive answer indicates that the reaction is in the direction of the applied unit force.

simples "

in metric?? lol

and dont say simples, my lecturer says that all the time!!!

Reply privately, Reply in forum +quote or View forums list

 

By (user no longer on site) OP     over a year ago


"yeah but to truely learn you must do it yourself so for your own good i am not going to help you "

pmsl cheers for that lol remember you said that when they find me delerious and banding my head on the wall lol

Reply privately, Reply in forum +quote or View forums list

 

By *illyrocCouple  over a year ago

north west


"yeah,all you have to do is Using equation (1), solve for YB:

-63200 (k-ft3)/EI + 2666.67 (k-ft3)/EI * YB = 0

YB = 23.7

Multiply the unit load, Q, at YB by 23.7 to get the final reaction. The positive answer indicates that the reaction is in the direction of the applied unit force.

simples "

All that workin out just to figure out if you have the right condom

Reply privately, Reply in forum +quote or View forums list

 

By *mumaWoman  over a year ago

Livingston

GOOGLE!!!!! can you tell I have no clue ( and not just about this post) xx

Reply privately, Reply in forum +quote or View forums list

 

By (user no longer on site) OP     over a year ago


"GOOGLE!!!!! can you tell I have no clue ( and not just about this post) xx"

thats why i am stuck even GOOGLE doesnt know !!! i keep asking, i even added please google just said i was needy

Reply privately, Reply in forum +quote or View forums list

 

By (user no longer on site)  over a year ago

So aliens do exist then cos I never heard this language spoken anywhere on Earth before.

Havre you guys been at the funny mushrooms again?

Reply privately, Reply in forum +quote or View forums list

 

By (user no longer on site)  over a year ago

Simply write first the compatibility equation, and find the deflections on the primary structure by using virtual work and find the flexibility coefficients by virtual work, too.

Reply privately, Reply in forum +quote or View forums list

 

By (user no longer on site)  over a year ago

......or have you asked Scotty for help with your beaming-up?

Reply privately, Reply in forum +quote or View forums list

 

By (user no longer on site)  over a year ago

Not sure, r u talking

- II theorem of Castillan

- Maxwell-Mors integrals

- Theorem of Vershchagin

here?

Reply privately, Reply in forum +quote or View forums list

 

By *ertnbeckyCouple  over a year ago

oldham

????????????????????

and thats all i have to say about that

Reply privately, Reply in forum +quote or View forums list

 

By (user no longer on site)  over a year ago

Do you mean deflections ? If you do .....

Simply write first the compatibility equation, and find the deflections on the primary structure by using virtual work and find the flexibility coefficients by virtual work, too.

For your case there is 1 compatibility equation of the form (considering deflections down positive):

Reply privately, Reply in forum +quote or View forums list

 

By (user no longer on site)  over a year ago


"Not sure, r u talking

- II theorem of Castillan

- Maxwell-Mors integrals

- Theorem of Vershchagin

here? "

can't be verschagin's because then you would have to include Logical operations and Kolmogorov complexities into the minimum length programs to translate between given strings

Reply privately, Reply in forum +quote or View forums list

 

By (user no longer on site)  over a year ago

Granny.

Google is indeed your friend, especially if you use spell checker too.

Reply privately, Reply in forum +quote or View forums list

 

By (user no longer on site)  over a year ago


" Granny.

Google is indeed your friend, especially if you use spell checker too. "

Laine. I did not use Google .... ffs ..... I worked it all out in my head.... I think he may have been talking about

Separate moment equations required for different regions of beam.

e.g.

After integrating equations separately to get slope and deflection equations, extra constants of

integration found by equating deflections and slopes at points where 2 equations apply, e.g. at

B.

integrating 2 equations twice gives 4 constants of integration

2 found by using v= 0 at A and C

2 found by equating slope and deflections at B.

Method becomes very complicated if more points loads - other simpler methods available

This tho really .........

Reply privately, Reply in forum +quote or View forums list

 

By (user no longer on site)  over a year ago

Oh alright ..... I got it from the same site as Be Nice .......

Reply privately, Reply in forum +quote or View forums list

 

By *iewMan  over a year ago
Forum Mod

Angus & Findhorn

I can write ESSO OIL on my calculator... well if I turn it upseide down it reads that...

does that help?

Reply privately, Reply in forum +quote or View forums list

 

By (user no longer on site)  over a year ago


"I can write ESSO OIL on my calculator... well if I turn it upseide down it reads that...

does that help?"

Can you do BOOBS tho ?

Reply privately, Reply in forum +quote or View forums list

 

By (user no longer on site)  over a year ago


"Oh alright ..... I got it from the same site as Be Nice ....... "

I'm still trying to get Scotty to beam up me.

Reply privately, Reply in forum +quote or View forums list

 

By (user no longer on site)  over a year ago


"Not sure, r u talking

- II theorem of Castillan

- Maxwell-Mors integrals

- Theorem of Vershchagin

here?

can't be verschagin's because then you would have to include Logical operations and Kolmogorov complexities into the minimum length programs to translate between given strings "

fair comment

Reply privately, Reply in forum +quote or View forums list

 

By *iewMan  over a year ago
Forum Mod

Angus & Findhorn


"I can write ESSO OIL on my calculator... well if I turn it upseide down it reads that...

does that help?

Can you do BOOBS tho ?"

sadly...... NO

Reply privately, Reply in forum +quote or View forums list

 

By (user no longer on site)  over a year ago


"Oh alright ..... I got it from the same site as Be Nice ....... "

fair comment

Reply privately, Reply in forum +quote or View forums list

 

By (user no longer on site)  over a year ago

Can anyone tell me the force required to hold a 10 tonne load, which is on steel wheels, on rails, on an incline of 29 degrees?

Also, is elastic stretch of steel wire proportional to load applied?

Serious questions

Reply privately, Reply in forum +quote or View forums list

 

By *iewMan  over a year ago
Forum Mod

Angus & Findhorn


"

Serious questions "

that rules me out.....

Reply privately, Reply in forum +quote or View forums list

 

By (user no longer on site)  over a year ago


"Can anyone tell me the force required to hold a 10 tonne load, which is on steel wheels, on rails, on an incline of 29 degrees?

Also, is elastic stretch of steel wire proportional to load applied?

Serious questions "

gerrof, sposed to be fun on ere!

Reply privately, Reply in forum +quote or View forums list

 

By (user no longer on site)  over a year ago

I'm doing homework with 12 yr old titch... much easier!

Reply privately, Reply in forum +quote or View forums list

 

By (user no longer on site) OP     over a year ago


"Can anyone tell me the force required to hold a 10 tonne load, which is on steel wheels, on rails, on an incline of 29 degrees?

Also, is elastic stretch of steel wire proportional to load applied?

Serious questions "

Force will be load * sin theta

So 10 tonne * 9.81 (Gravity) * sin29

ie.

10*10^3 * 9.81 * sin29

= 47559 kN

I think

Also

strench is due to strain and strain is proportional to stress, stress as iduced by the load.

So yes....its youngs modulus

Reply privately, Reply in forum +quote or View forums list

  

By (user no longer on site)  over a year ago


"yeah,all you have to do is Using equation (1), solve for YB:

-63200 (k-ft3)/EI + 2666.67 (k-ft3)/EI * YB = 0

YB = 23.7

Multiply the unit load, Q, at YB by 23.7 to get the final reaction. The positive answer indicates that the reaction is in the direction of the applied unit force.

simples "

fookin teachers pet!

Reply privately, Reply in forum +quote or View forums list

» Add a new message to this topic

0.0156

0