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By (user no longer on site) 52 weeks ago
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I always thought "Bob Dylan's 115th Dream" was about Captain Ahab, but now I have looked up the lyrics on line it says Captain Arab - though I still like the line:
Well, the last I heard of Arab
He was, stuck on a whale
That was married to the deputy, sheriff of the jail |
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By (user no longer on site) 52 weeks ago
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"I have a Mobius dick  does that mean wherever you start you always end up on the the other side "
No, it means my dick is an abstract topological space, my Möbius dick can be embedded into three-dimensional Euclidean space in many different ways: a clockwise half-twist is different from a counterclockwise half-twist, and it can also be embedded with odd numbers of twists greater than one, or with a knotted frenulum. Any two embeddings with the same knot for the frenulum and the same number and direction of twists are topologically equivalent. All of these embeddings have only one shaft, but when embedded in other spaces, my Möbius dick may have two shafts. It has only a single boundary curve. |
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"I have a Mobius dick does that mean wherever you start you always end up on the the other side
No, it means my dick is an abstract topological space, my Möbius dick can be embedded into three-dimensional Euclidean space in many different ways: a clockwise half-twist is different from a counterclockwise half-twist, and it can also be embedded with odd numbers of twists greater than one, or with a knotted frenulum. Any two embeddings with the same knot for the frenulum and the same number and direction of twists are topologically equivalent. All of these embeddings have only one shaft, but when embedded in other spaces, my Möbius dick may have two shafts. It has only a single boundary curve."
Obviously  |
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"I have a Mobius dick does that mean wherever you start you always end up on the the other side
No, it means my dick is an abstract topological space, my Möbius dick can be embedded into three-dimensional Euclidean space in many different ways: a clockwise half-twist is different from a counterclockwise half-twist, and it can also be embedded with odd numbers of twists greater than one, or with a knotted frenulum. Any two embeddings with the same knot for the frenulum and the same number and direction of twists are topologically equivalent. All of these embeddings have only one shaft, but when embedded in other spaces, my Möbius dick may have two shafts. It has only a single boundary curve.
Obviously "
Hi Alexa |
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