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Anyone here good at maths?
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By *mily36CWoman
over a year ago
Beds (or anywhere beginning with B..!?) |
Nop, only When insomnia has kicked in in the middle of the night and start calculating exactly how much sleep I could still get if fell back to sleep straightaway!?
...so catch me then!  |
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By *ean counterMan
over a year ago
Market Harborough / Kettering |
I managed to get a high grade O level in maths as I really enjoy it (weird I know) but this has come in handy considering my job now 
Also comes in handy when Im counting sheep in my head when I cant sleep at night |
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By (user no longer on site)
over a year ago
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We both work with numbers in different fields in finance.
I'd say my maths skills are pretty decent, but seriously some of the stuff my nearly teenage daughter brings home from school makes my brain hurt  |
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"Was.. not so much now... as they say if you don't use it you loose it..
Electrical and electronic engineering degrees are pretty much maths based throughout..  "
It’s mad ain’t it. What I had to do tis get qualified vs what I actually use in job.
I was a master at using trig to work out power factors on motors at one point. Not so much anymore |
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By *ty31Man
over a year ago
NW London |
"Was.. not so much now... as they say if you don't use it you loose it..
Electrical and electronic engineering degrees are pretty much maths based throughout..
It’s mad ain’t it. What I had to do tis get qualified vs what I actually use in job.
I was a master at using trig to work out power factors on motors at one point. Not so much anymore "
Same. Had to learn loads of complex maths (imaginary numbers, integration, differentiation etc) when I studied engineering. Now I've gotten so rusty with all of it through lack of use! |
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By *mily36CWoman
over a year ago
Beds (or anywhere beginning with B..!?) |
"I managed to get a high grade O level in maths as I really enjoy it (weird I know) but this has come in handy considering my job now
Also comes in handy when Im counting sheep in my head when I cant sleep at night "
Can I borrow some of those sheep?! |
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I'm mathsy enough to know that 3 minutes have passed since I offered my services......... pah!
I have things to do in this time continuum ..... I must awayyyyyy Hi Hooooooooo silverrrrrrrrrrrrrrrr....... up up and awayyyyyyy
Sorry i've been back to backing The Tick ....... I have the hots for Peter Seranefowicz ..... ( it's okay to spell it wrong - he doesn't come here ) |
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By *ettaMan OP Man
over a year ago
Kerry and Dublin |
"I did it to university level. "
Oh cool! That would probably be the level required. I think, I'm not sure.
It's a question about proving a proposition about 3D space. Like, determining rules for how objects can move from one region to another at a finite speed.
Would that be in your ball park? |
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By *ettaMan OP Man
over a year ago
Kerry and Dublin |
"Yes. Ask me anything......... I'm waiting to solve.....  "
Is it possible to prove that for anything (object/causal influence) to propagate between two spatially separated regions of 3D space, A and B, that it must pass through region C (which = not A+B).
Further, that it must travel a unique path through C? |
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By (user no longer on site)
over a year ago
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"Yes. Ask me anything......... I'm waiting to solve.....
Is it possible to prove that for anything (object/causal influence) to propagate between two spatially separated regions of 3D space, A and B, that it must pass through region C (which = not A+B).
Further, that it must travel a unique path through C?"
what do you mean by propogate ? I'm assuming you mean move in a straight line?
And assuming you mean from any point X (in A) to any point by (in B) there's a unique line. Rather than all points x and y there is the same path.
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"Was.. not so much now... as they say if you don't use it you loose it..
Electrical and electronic engineering degrees are pretty much maths based throughout..
It’s mad ain’t it. What I had to do tis get qualified vs what I actually use in job.
I was a master at using trig to work out power factors on motors at one point. Not so much anymore
Same. Had to learn loads of complex maths (imaginary numbers, integration, differentiation etc) when I studied engineering. Now I've gotten so rusty with all of it through lack of use!"
Pretty much all of the above..
I have never needed partial differentiation to determine that a circuit has a fault. Freezer spray, a circuit diagram and a good nose repaired 99% of problems. now if I was designing filters for complex signalling. Then perhaps yes. But even then I'd be using a computer program. |
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By (user no longer on site)
over a year ago
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I was in top set at Maths at school and my general arithmetic is pretty good (years of watching Countdown helps ).
Problem is 95% of the stuff you learnt at school you never use in day to day life so I'd struggle to remember it now if required. |
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"Yes. Ask me anything......... I'm waiting to solve.....
Is it possible to prove that for anything (object/causal influence) to propagate between two spatially separated regions of 3D space, A and B, that it must pass through region C (which = not A+B).
Further, that it must travel a unique path through C?what do you mean by propogate ? I'm assuming you mean move in a straight line?
And assuming you mean from any point X (in A) to any point by (in B) there's a unique line. Rather than all points x and y there is the same path.
"
Depends whether you accept the parallel proposition ie. Euclidean vs non-euclidean space.
For any sort of proof need details about what type of vector spaces we are talking, and I'd have to swot up on my very ancient knowledge of linear algebra. |
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1 Normed Spaces. Banach Spaces.
1.1 Vector Space.
Definition 1.1.
1. An arbitrary subset M of a vector space X is said to be linearly independent if
every non-empty finite subset of M is linearly independent.
2. A vector space X is said to be finite dimensional if there is a positive integer
n such that X contains a linearly independent set of n vectors whereas any set of
n + 1 or more vectors of X is linearly dependent. n is called the dimension of X,
written n = dim X.
3. If X is any vector space, not necessarily finite dimensional, and B is a linearly
independent subset of X which spans X, then B is called a basis (or Hamel
basis) of X.
¥Hence if B is a basis for X, then every nonzero x 2 X has a unique repre-
sentation as a linear combination of (finitely many!) elements of B with
nonzero scalars as coefficients.
hope this helps  |
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By *ettaMan OP Man
over a year ago
Kerry and Dublin |
"
Depends whether you accept the parallel proposition ie. Euclidean vs non-euclidean space.
For any sort of proof need details about what type of vector spaces we are talking, and I'd have to swot up on my very ancient knowledge of linear algebra."
Would it be possible to demonstrate that it applies to any/all 3D vector spaces? |
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By *ettaMan OP Man
over a year ago
Kerry and Dublin |
"I studied astrophysics and quantum mechanics at uni so....."
Cool! I'd love to go back and study it now.
Would you know the answer?
(For some reason I can't send the full response I have typed) |
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"
Depends whether you accept the parallel proposition ie. Euclidean vs non-euclidean space.
For any sort of proof need details about what type of vector spaces we are talking, and I'd have to swot up on my very ancient knowledge of linear algebra.
Would it be possible to demonstrate that it applies to any/all 3D vector spaces?"
I'm very rusty on this stuff (though funnily enough was re-reading a bit of vector algebra for fun  quite recently). I think that within an R3 space it should be possible to prove a unique shortest path including points A, B and C, where A, B and C are distinct, as long as the space is free of singularities. Where "shortest" is with respect to whatever metric, be it a distance measure, time measure, lowest energy path etc. The path is essentially the geodesic that takes in all three points.
With singularities, there may be the possibility of several geodesics going different ways around a singularities?
Putting this into the context of real physical space I think it means that in the vicinity of a black hole all bets are off, but in areas of asymptotically flat space there will be unique paths.
But don't quote me on any of that in your PhD thesis!! |
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By *ean counterMan
over a year ago
Market Harborough / Kettering |
"
Depends whether you accept the parallel proposition ie. Euclidean vs non-euclidean space.
For any sort of proof need details about what type of vector spaces we are talking, and I'd have to swot up on my very ancient knowledge of linear algebra.
Would it be possible to demonstrate that it applies to any/all 3D vector spaces?
I'm very rusty on this stuff (though funnily enough was re-reading a bit of vector algebra for fun quite recently). I think that within an R3 space it should be possible to prove a unique shortest path including points A, B and C, where A, B and C are distinct, as long as the space is free of singularities. Where "shortest" is with respect to whatever metric, be it a distance measure, time measure, lowest energy path etc. The path is essentially the geodesic that takes in all three points.
With singularities, there may be the possibility of several geodesics going different ways around a singularities?
Putting this into the context of real physical space I think it means that in the vicinity of a black hole all bets are off, but in areas of asymptotically flat space there will be unique paths.
But don't quote me on any of that in your PhD thesis!! "
Bloody hell! What a coincidence, that just what I was going to say |
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"Im great at maths, just need numbers to work with. Havent seen any numbers since scrolling through this thread. Not a single"
That's rubbish cos I posted numbers...
I have a scientific calculator which I used to tell me what cos & tan were as numbers & went from there as an equation...
No one has said if it was correct or not though |
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By *otMe66Man
over a year ago
Terra Firma |
Fastest mathematicians known to man?
The 1980's pub team dart players
They would be able to drink 20 pints of ale, throw spears into a dartboard with amazing accuracy and subtract triple / double and single digits faster than I could use a calculator.
I think they are now extinct |
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By *ettaMan OP Man
over a year ago
Kerry and Dublin |
"
Depends whether you accept the parallel proposition ie. Euclidean vs non-euclidean space.
For any sort of proof need details about what type of vector spaces we are talking, and I'd have to swot up on my very ancient knowledge of linear algebra.
Would it be possible to demonstrate that it applies to any/all 3D vector spaces?
I'm very rusty on this stuff (though funnily enough was re-reading a bit of vector algebra for fun quite recently). I think that within an R3 space it should be possible to prove a unique shortest path including points A, B and C, where A, B and C are distinct, as long as the space is free of singularities. Where "shortest" is with respect to whatever metric, be it a distance measure, time measure, lowest energy path etc. The path is essentially the geodesic that takes in all three points.
With singularities, there may be the possibility of several geodesics going different ways around a singularities?
Putting this into the context of real physical space I think it means that in the vicinity of a black hole all bets are off, but in areas of asymptotically flat space there will be unique paths.
But don't quote me on any of that in your PhD thesis!! "
Cheers for this. It's not exactly what I was inquiring about, but it's interesting nonetheless.
My wording was probably a bit unclear. I wasn't necessarily looking to prove the shortest path between A and B or that the shortest path must contain a point in C. More generally, that all paths between A and B must have a point in C.
It seems like a pretty obvious proposition, but I wouldn't be able to prove it mathematically. |
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By *ettaMan OP Man
over a year ago
Kerry and Dublin |
"Im great at maths, just need numbers to work with. Havent seen any numbers since scrolling through this thread. Not a single"
Can you prove that all paths between A and B must contain a point in C though? |
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By (user no longer on site)
over a year ago
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Is C defined as being non empty?
Even then I think that if A and B share a boundary then you can draw a path
Eg A = circle radius 1
B = donut with hole radius = 1 (with the boundray r = 2 being part of B) then I can get from A to B without giving through C. Zenos paradox type territory. |
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By (user no longer on site)
over a year ago
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"Im great at maths, just need numbers to work with. Havent seen any numbers since scrolling through this thread. Not a single"
as my maths teacher used to say ones all the equations were lined up "that's the maths done, the rest are just sums".
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